Solve the system of equations. -12x-5y=40 and 12x-11y=88 x= y=

(0,-8)

x=0

y=-8

Step-by-step explanation:

There are a couple of ways you can solve this I used what I think is called the elimination method

We first start by writing the equations in linear form (y=mx+b)

For the first one we have -12x-5y=40

we add 5y to both sides and subtract 40 to get

-12x-40=5y

divide by 5 to get

-12/5x-8=y

Then the second one we have

12x-11y=88

same deal here, add 11y and subtract 88 to get

12x-88=11y

divide by 11 and get

12/11x-8=y

We then set the two equations equal to each other and get

-12/5x-8=12/11x-8

We can add 8 to both sides and get

-12/5x=12/11x

Just by looking at it you can see that the only solution for x is 0

Plug in 0 to the first equation and get -12*0-5y=40

This means that -5y=40

Solve for y and get -8

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)