What is the slope of the line that passes through the points (0,5) (2,10)

m=5/2

Step-by-step explanation:

the equation of slope is (y2-y1)/(x2-x1)

here are the points given: (0,5), (2,10)

let's label the points:

x1=0

y1=5

x2=2

y2=10

now substitute into the equation (m is the slope)

m=(10-5)/(2-0)

subtract

m=5/2

the slope is 5/2

the answer is n

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180