The longest length side of an acute isosceles triangles is 12 centimeters. Rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides

8.5

Step-by-step explanation:

Given that;

The longest side of an acute isosceles triangle = 12 centimeters

Since the two remaining sides are congruent, then they both have the same length ;

Let the length of the two remaining sides = 2x,

The length of each side :

Length of longest side / sqrt(2)

x = 12 /sqrt(2)

x = 12 / 1.4142135

x =8.4852813

x = 8.5

idc

step-by-step explanation:

idk

70

step-by-step explanation: