Solve 0=x^2 +6x+13 by completing the square

No real solutions

Step-by-step explanation:

0=x^2+6x+13

Step 1: Subtract x^2 from both sides.

0−x^2=x^2+6x+13−x^2

−x^2=6x+13

Step 2: Subtract 6x from both sides.

−x^2−6x=6x+13−6x

−x^2−6x=13

Step 3: Since the coefficient of -x^2 is -1, divide both sides by -1.

−x^2−6x/−1 = 13/−1

x^2+6x=−13

Step 4: The coefficient of 6x is 6. Let b=6.

Then we need to add (b/2)^2=9 to both sides to complete the square.

Add 9 to both sides.

x^2+6x+9=−13+9

x^2+6x+9=−4

Step 5: Factor left side.

(x+3^)2=−4

Step 6: Take square root.

x+3=±√−4

Step 7: Add -3 to both sides.

x+3+−3=−3±√−4

x=−3±√−4

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for