Two solutions of salt water contain 0.03% and 0.18% salt respectively. A lab technician wants to make 1 liter of solution which contains 0.06% salt. How much of each solution should she use?

0.8 L of 0.03% solution and 0.2 L of 0.18% solution

Step-by-step explanation:

Let x and 1 - x be the amount of salt water in liter with 0.03% and 0.18% salt respectively.

0.03 % = 0.0003

0.18 % = 0.0018

0.06 % = 0.0006

0.0003x + 0.0018(1 - x) = 0.0006(1)

0.0003x + 0.0018 - 0.0018x = 0.0006

0.0012 = 0.0015x

x = 0.0012/0.0015

x = 0.8 L

1 - x = 0.2 L

no idea

step-by-step explanation:

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: