What’s the answer I’ll give brainliest(you gotta tell me how to give brainliest too)

B.

Step-by-step explanation:

When we're talking about a restricted domain, we're looking for a function that's undefined for certain values of x. A classic example is the function f(x) = 1/x. Division by 0 is undefined, so this restricts our domain to all real numbers except 0.

A key feature of our problem is in the exponents - are there any exponents that would limit the possible values of x? Let's strip away the rest of the details and just look at those powers for each option:

For A, let's look at the function . Remember that fractional exponents are the same as roots, so we could also say . Any odd root like this can take any value for x, positive and negative. This has to do with the fact that any odd power of a negative is always negative. So no restrictions on A.

For B, just looking at the exponent, let's see if there are restrictions on the function . Again, we can rewrite the right side as a root: .

Unline f(x), k(x) is restricted. The square root of a negative number has no real solutions, so k(x) comes with the restriction that x ≥ 0. We could look at C and D, but we've already found our solution at this point, so I'll stop here!

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

wedfghjkl;

tyuiop[]ghjkl;

step-by-step explanatio89