-3 + 42 > 3

x > 15
x < 15
x > 13
x < 13

Where's the x?

I am assuming that the problem must be

-3 + 42 > 3x

if that is true, then

x < 13.

As this statement is, -3 + 42 > 3 is a true statement because -3 + 42 = 39, and

39 > 3 [39 is always greater than 3]

Step-by-step explanation:

Let me know if you need a step by step.

D) x < -15

Step-by-step explanation:

-3x - 42 >3

Add 42 to each side

-3x - 42+42 >3+42

-3x > 45

Divide each side by -3.  Remember to flip the inequality since we are dividing by a negative

-3x/-3 < 45/-3

x < -15

not really sure how you want this solved but the equation itself is true

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3