Determine algebraically, three consecutive integers such that the sum of the first and the third is three times the second

x,x+1,x+2

Step-by-step explanation:

x+2[x+1]+3[x+2]= -76

x+2x+2+3x+6= -76

6x+8=-76

6x=-76-8

6x= -84

x= -84/6

x= -14

hope it helps UvU

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

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