The tables show the relationships between x and y for two data sets. Which statements describe the relationships between x and y in Data Set I and Data Set II?

Both data sets show additive relationships.
In Data Set I, y is 5.5 more than x , and in Data Set II, y is 5 more than x .

Data Set I shows a multiplicative relationship in which y is 5.5 times x .

Data Set II shows an additive relationship in which y is 20 more than x .

Both data sets show multiplicative relationships.
In Data Set I, y is 5.5 time
s x, and in Data Set II, y is 5 times x .

Data Set I shows an additive relationship in which y is 4.5 more than x .
Data Set II shows a multiplicative

3/6 chance

step-by-step explanation:

half of the nubers are odd numbers (1,3,5) which in that case if you would be told to simplify it would be 1/2

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x

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convert the exponential equation to a logarithmic equation using the logarithm base (6) of the right side (36) equals the exponent (2).

ℓσg6(36)=2

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