Mr. And Mrs. Doran have a genetic history such that the probability that a child being born to them with a certain trait is 0.14. If they have seven children, what is the probability that at most two of their seven children will have that trait? Round your answer to the nearest thousandth.

0.938

Step-by-step explanation:

From the question :

p = 0.14

Number of children, n = 7

P(x ≤ 2) = P(2) + P(1) + P(0)

Using binomial probability :

P(x =x) = nCx  * p^x * (1 - p)^(n - x)

We could also use the binomial probability calculator :

P(x ≤ 2) = 0.3479 + 0.3965 + 0.1936

P(x ≤ 2) = 0.938

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

answer: no

step-by-step explanation: because the big angle will spread away the 2 side that it is on and make the opposite side even longer.