The difference between two number is 40 if the smaller number is divided by the large number the fraction obtained is 6/11 find the number

48 and 88

Step-by-step explanation:

let the 2 numbers be x and y , then

x - y = 40 → (1)

= ( cross- multiply )

6x = 11y → (2)

From (1) x = 40 + y → (3)

Substitute x = 40 + y into (2)

6(40 + y) = 11y

240 + 6y = 11y ( subtract 6y from both sides )

240 = 5y ( divide both sides by 5 )

48 = y

Substitute y = 48 into (3)

x = 40 + 48 = 88

The 2 numbers are 48 and 88

answer: idk

step-by-step explanation: