Solve using the quadratic formula

w =  or w =

Step-by-step explanation:

5w^2 - 90 = 0

5w^2 + 0w - 90 = 0

aw^2 + bw + c = 0 ----> a = 5, b = 0, c = -90

  or  

 or  

or  

Hope this helps!

c) yes, because of asa or aas

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v