Given \small \Delta ABC\sim\Delta DEC, could you use the proportion \small \frac{9}{10}=\frac{8.75}{EC} to determine the measure of EC? If yes, type yes and solve for EC. (Must type yes and give value of EC) If no, type no and rewrite the proportion and then solve for EC. (Must type no, give the correct proportion, and the value of EC)

the answer is. -82562234434584

step-by-step explanation:

b. x + 1

step-by-step explanation:

i'am smart

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

do you have a picture of the table