The steps below describe the construction of a line AG which is parallel to segment PQ and passes through a point A outside of PQ: Point G is obtained by using the same compass width and drawing an arc from point E, intersecting the arc drawn from A.
Point G is obtained by using the same compass width and drawing an arc from point B, intersecting the arc drawn from A.
Point G is obtained by using the same compass width and drawing an arc from point D, intersecting the arc drawn from A.
Point G is obtained by using the same compass width and drawing an arc from point F, intersecting the arc drawn from A.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

hc ghfrfgb

step-by-step explanation:

gedfgb nbgfrezrdfgbn bgfderdfgbvn bvfdsvcb bvfdfgb gfdgb gfr

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct

i don't know i don't know