A person invests 9000 dollars in a bank. The bank pays 4.75% interest compounded quarterly. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 12600 dollars? A=P(1+nr)nt

The time required to get  a total amount of $ 12,600.00  from compound interest on a principal of $9000  at an interest rate of 4.75% per year  and compounded 4 times per year  is 7.1 years.

Step-by-step explanation:

Given

Principle P = 9000 dollars

Rate r = 4.75% = 0.0475

Total Amount A = 12600 dollars

compounded quarterly n = 4

To determine:

Time t = ?

Using the equation

solving the equation for 't'

t = ln(A/P) / n[ln(1 + r/n)]

t = ln(12,600.00/9,000.00) / ( 4 × [ln(1 + 0.011875/4)] )

t = 7.1 years

Therefore, the time required to get  a total amount of $ 12,600.00  from compound interest on a principal of $9000  at an interest rate of 4.75% per year  and compounded 4 times per year  is 7.1 years.

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.