The point (-2,3) is the solution to a system of two linear equations. Which of the following can be one of the equations?
A. y=3x-2
B.-x+1
C. y=x-1
D. y=2x+3

We conclude that The point (-2, 3) satisfies the equation y = -x+1.

Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.

Step-by-step explanation:

Given

Checking option A

Given the equation

y = 3x-2

substitute x = -2 and y = 3

3 = 3(-2) - 2

3 = -6 - 2

3 = -8

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y = 3x-2.

Checking option B

Given the equation

y = -x+1

substitute x = -2 and y = 3

3 = -(-2)+1

3 = 2+1

3 = 3

TRUE!

L.H.S = R.H.S

Thus,

The point (-2, 3) satisfies the equation y = -x+1.

Checking option C

Given the equation

y=x-1

substitute x = -2 and y = 3

3 = -2-1

3 = -3

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y=x-1.

Checking option D

Given the equation

y=2x+3

substitute x = -2 and y = 3

3 = 2(-2)+3

3 = -4+3

3 = -1

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y=2x+3.

Conclusion:

Thus, we conclude that The point (-2, 3) satisfies the equation y = -x+1.

Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.

idk

step-by-step explanation:

idk

answer: i'm not sure

step-by-step explanation: