PLEASE HELP In ΔABC shown below, segment DE is parallel to segment AC:

Triangles ABC and DBE where DE is parallel to AC

The following two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally:

Statement Reason

1. Line segment DE is parallel to line segment AC 1. Given

2. Line segment AB is a transversal that intersects two parallel lines. 2. Conclusion from Statement 1.

3. ∠BDE ≅ ∠BAC 3. Corresponding Angles Postulate

4. 4.

5. 5.

6. BD over BA equals BE over BC 6. Converse of the Side-Side-Side Similarity Theorem

Which statement and reason accurately completes the proof?

A)
4. ΔBDE ~ ΔBAC; Side-Angle-Side (SAS) Similarity Postulate

5. ∠B ≅ ∠B; Reflexive Property of Equality

B)
4. ∠B ≅ ∠B; Reflexive Property of Equality

5. ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate

C)
4. ΔBDE ~ ΔBAC; Side-Angle-Side (SAS) Similarity Postulate

5. ∠A ≅ ∠C; Isosceles Triangle Theorem

D)
4. ∠A ≅ ∠C; Isosceles Triangle Theorem

5. ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate