+me i beg you i really need
find the slope of the line that passes through the points (8, 7) and (11, 7).
which is not a step used when constructing a perpendicular from a point not on a given line?
without changing the compass, from each intersecting arc on the line, construct two arcs on the side opposite the given point.
use your ruler and draw a straight line from the point through the line.
from the point not on the line stretch the compass and mark two arcs on the line.
draw a line from the point to the intersecting arcs.

(8,7)(11,7)when u have y values that r the same, it is a horizontal line. A horizontal line has a slope of 0.

not 100% surebut I think it may be B

point F is (-2,3)

P = a + b + c
a = (-8,-4), b = (-7,-8), c = (-6,-2)
distance from a to b = 4.12
distance from a to c = 2.83
distance from b to c = 6.08
P = 4.12 + 2.83 + 6.08 = 13.03 <==

d = sqrt W^2 + L^2
d = sqrt 9^2 + 5^2
d = sqrt (81 + 25)
d = sqrt 106
d = 10.30 <==

3x + 1 = 1/3x + 9...multiply by 3
9x + 3 = x + 27
9x - x = 27 - 3
8x = 24
x = 24/8
x = 3

AK = 3x + 1
AK = 3(3) + 1
AK = 9 + 1
AK = 10

Line B has a slope of 2

There is no association.