Two of the tangents to a circle meet at Q, which is 25 cm from the center. The circle has a 7-cm radius. To the nearest tenth of a degree, find the angle formed at Q by the tangents.

31.3

Step-by-step explanation:

Calculation to find the angle formed at Q by the tangents

First step is to use the tangent of the angle to calculate half the angle (A) at Q

Tan(A) =7-cm radius/25 cm

Tan A = 15.64

Since since we were told that two of the tangents to a circle meet at Q, Now let calculate the angle formed at Q by the tangents

Angle at Q(Tangents)=2*15.64

Angle at Q(aTangents)= 31.3

Therefore the angle formed at Q by the tangents will be 31.3

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8