The one-to-one functions g and h are defined as follows.
HELP PLEASE

2, (x+13)/6, -7

Step-by-step explanation:

The -1 bit means do it backwards, so look the for the output of the function with the value given.

In g, when we put in 2 we get 9 out, so g^-1(9) is 2.

For the second one we need to rearrange it to get x = something.

h(x) + 13 = 6x

x = (h(x) + 13)/6

Then replace the h(x) with x and the x with h^-1(x) to get

h^-1(x) = (x + 13)/6

The last one is a trick. Note that h and h^-1 are opposites. If we do something then do the opposite of it, we haven't done anything at all! So the number stays the same.