(1) A cube of ice has side length of 5cm. The mass of the cube of ice is 114.5g.
Find the density of ice.
Give your answer in g/cm3

0.916g/cm³

Step-by-step explanation: multiply 5×5×5 to find the volume: 125cm³

Divide the given mass, 114.5 ÷ 125 = 0.916

Density of Ice = 0.916 g/cm^3

Step-by-step explanation:

Length of Cube of ice = 5 cm

Mass of Cube = 114.5 g

We need to find density of ice.

The formula used to find density of ice is:

Before. finding density, we need to find volume of cube of ice.

The formula used for finding volume is:

We have Length = 5

So, Volume will be:

We get Volume of cube of ice = 125

Now finding density

So, We get Density = 0.916 g/cm^3

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.