At a grocery store, there is a 62% chance that a customer will pay with a credit card and a 25% chance that a customer will pay with cash. 12% of the customers uses both ways to pay. What is the probability that a randomly selected customer will pay with a credit card or with cash?

The probability that a randomly selected customer will pay with a credit card or with cash

P(CD ∪C ) = 0.75 = 75%

Step-by-step explanation:

Explanation:-

Given the chance that a customer will pay with a credit card

P(CD) = 62 % =0.62

Given the chance that a customer will pay with a cash

P(C) = 25% =0.25

Given the chance that a customer will pay both

P(CD ∩ C) = 12% = 0.12

The probability that a randomly selected customer will pay with a credit card or with cash

P(CD ∪C ) = P( CD ) + P(C) - P( CD∩C)

                = 0.62+0.25 -0.12

               = 0.75

Final answer:-

The probability that a randomly selected customer will pay with a credit card or with cash

P(CD ∪C ) = 0.75

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form