7. Given the points R(-5, 3), 5(-5, 4), 7(-3, 4), and U(-3, 1), which line is perpendicular to TU?
A: RS
B: RT
C: ST
D: SU

C: ST

Step-by-step explanation:

Perpendicular Lines

The four points R(-5, 3), S(-5, 4), T(-3, 4), and U(-3, 1) are shown in the image attached below.

The vertical line TU is also shown. The only possible line perpendicular to TU is ST because it's a horizontal line.

Horizontal lines have a slope of 0. Let's verify the slope between points S(-5,4) and T(-3,4):

Once verified, the answer is C: ST

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}