How would you solve the equation y=3x-11 with 0=6x-2y-22 using systems by substitution? Pls i need help with this

x=0 y=-11 (0,-11)

Step-by-step explanation:

1. take what y equals (3x-11) and plug it in for y in the second equation

Should look like this: O= 6x-2(3x-11)-22

2. Then distribute O=6x-6x+22-22

3. Then combine like terms O= 0 the 22's cancel out as well as the x's

x= 0

4. plug 0 in for x in the first equation y=3(0)-11

5. y= -11

6. x=0 y=-11 (0,-11)

This is the answer

x=0 y=-11 (0,-11)

Hope I helped! :)

Step-by-step explanation:

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