A researcher wishes to estimate the proportion of adults in the city of Darby who are vegetarian. In a random sample of 1,613 adults from this city, the proportion that are vegetarian is 0.075. Find a 90% confidence interval for the proportion of all adults in the city of Darby that are vegetarians. Group of answer choices

90% confidence interval for the proportion of all adults in the city of Darby that are vegetarians

(0.0643075 , 0.0856925)

Step-by-step explanation:

Explanation

Size of the random sample  'n' = 1613

The proportion of the  vegetarian p = 0.075

Level of significance = 0.10

90% confidence interval for the proportion of all adults in the city of Darby that are vegetarians

( 0.075 - 1.645 × 0.0065 ,  0.075 +1.645 × 0.0065)

( 0.075 -0.0106925 , 0.075+0.0106925)

(0.0643075 , 0.0856925)

Final answer:-

90% confidence interval for the proportion of all adults in the city of Darby that are vegetarians

(0.0643075 , 0.0856925)

the ratio of balloons to tables is 5: 2 and the constant variation is 5.

the equation is y=5x

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.