Suppose that a recent poll of American households about pet ownership found that for households with pets, 45% owned a dog, 34% owned a cat, and 10% owned a bird. Suppose that three households are selected randomly and with replacement and the ownership is mutually exclusive. What is the probability that all three randomly selected households own a dog

The probability that all three randomly selected households own a dog  is

0.091125.

Given that,

Based on the above information, the calculation is as follows:

= 0.091125

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0.091125

Step-by-step explanation:

Given : P(dog) = 0.45

If 3 households are selected randomly and with replacement and the ownership is mutually exclusive.

Then , probability that all three randomly selected households own a dog =

Hence, required probability = 0.091125

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0