Jim has a bag that contains 8 red marbles, 15 blue marbles, and 17 yellow marble, He takes 1 marble at random from the bag and does not replace. then he takes another marble from the bag at random. what is the probability that Jim chooses a red marble fist and blue marble second? Please help me A. 3/40
B. 1/13
C. 8/15
D. 2/39

Find total marbles:

8 + 15 + 17 = 40 total marbles.

There is 8 red, so picking red first would be 8/40, which can reduce to 1/5.

After taking 1 marble there would be 39 marbles left.

Picking blue would be 15/39, which reduces to 5/13

The probability of doing both is

1/5 x 5/13 = 5/65, which reduces to 1/13

The answer is B. 1/13

idk man good luck man