Find the equation of a quadratic function with zeros at x = 2 and x = 4 and y-intercept (0,8). Give your answer in standard form. Question 10 options:

f(x) = –(x – 2)(x – 4)

f(x) = –x2 + 6x – 8

f(x) = x2 – 6x + 8

f(x) = (x – 2)(x – 4)

Multiply 9 and 67. then multiply 3 with 67. lastly the answer that you got for 9x67 is to be subtracted by the answer you got for 3x67

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60