Write an equation of a line in slope-intercept form that passes through (-3,5) and is parallel to y = -6x +1. Then find its x- and y-intercepts.

a) The equation of the Parallel line to the given straight line is

       6 x + y + 13 =0

b) Slope - intercept form

        y = - 6 x - 13

c) The intercept - form

x - intercept  =  

y - intercept = - 13

Step-by-step explanation:

Step(i):-

Given the equation of the straight line

                             y = -6x +1

                  6 x + y - 1 = 0

The equation of the Parallel line to the given straight line is

                6x + y + k=0 and it passes through the point (-3, 5 )

           ⇒ 6 (-3 ) + 5 + k =0

          ⇒  - 18 + 5 + k=0

         ⇒   -13 + k = 0

        ⇒     k = 13

The equation of the Parallel line to the given straight line is

       6 x + y + 13 =0

Step(ii):-

Slope - intercept form

                y = m x + C

                y = - 6 x - 13

Step(iii):-

Intercept - form

              6 x + y + 13 =0

              6 x + y = - 13

The intercept - form

x - intercept  =  

y - intercept = - 13

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: