The initial amount of bacteria in a culture is 12,000. The culture grows at a rate of 45% each day. Write an exponential function to model the population of y bacteria after x days. How many bacteria are there after 6 days?

FV= 111,529.37 = 111,529

Step-by-step explanation:

Giving the following information:

Initial amount (PV)= 12,000

Growth rate (g)= 45% = 0.45

First, we will establish the future value formula:

FV= PV*(1+g)^n

FV= future value

n= number of days

FV= 12,000*(1.45^n)

For 6 days:

FV= 12,000*(1.45^6)

FV= 111,529.37

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

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answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column