In a grid of an auditorium, the vertices of a section of seats are A(40, 20) , B(80, 20) , C(100, 70) , and D(40, 70) . The coordinates are measured in feet. Find the area of the section.

Step-by-step explanation:

Given

Required

Determine the Area

The area of the section is:

Substitute values for the x's and y's

Hence, the area of the section is 2900ft^2

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

135 is your answer

step-by-step explanation:

try 180 times three then divide that number by 4 (sides) to get your answer. im glad to : )