Consider the line y = 7x-3. What is the slope of a line parallel to this line?
What is the slope of a line perpendicular to this line?

Gradient of parallel line= 7

Gradient of perpendicular line

Step-by-step explanation:

The equation of the line is already in slope-intercept form (y= mx +c). This means that the coefficient of x is the gradient and the constant -3 is the y-intercept of the line.

y= 7x -3

Gradient= 7

Parallel lines have the same gradient.

Thus, the slope of the line parallel to this line is also 7.

The product of the gradients of 2 perpendicular lines is -1.

(Gradient of perpendicular line)(7)= -1

Gradient of perpendicular line

= -1 ÷7

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

fd

step-by-step explanation: