HELP PLEASE I'LL GIVE BRAINIEST IF YOUR RIGHT Which is the equation of a hyperbola with directrices at x = ±2 and foci at (4, 0) and (−4, 0)?

x squared over 8 minus y squared over 8 equals 1
x squared over 8 minus y squared over 16 equals 1
y squared over 8 minus x squared over 8 equals 1
y squared over 16 minus x squared over 8 equals 1

y²/12 - x²/24= 1

Step-by-step explanation:

give me brainliest pls

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°