Help. Please show workings.
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Question :
1. Find the gradient of the tangent to the curve y = 2x²+5x-3 at the point where x = 1.

2. Find from first principle, the derivative of 3/x with respect to x

dy/dx

= d/dx [2x² + 5x - 3]

= 4x + 5.

Hence at x = 1, dy/dx = 4(1) + 5 = 9.

The slope of the tangent is 9.

d/dx (3/x)

= d/dx (3x^-1)

= 3 * d/dx (x^-1)

= 3 * [-1 * x^(-2)]

= -3/x².

think about it deeply and passionately about this property

i am sorry

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,