Carl has three lengths of cable, 5/6 yard long, 1/4 yard long, and 2/3 yard long. If he uses 1 yard of cable, how much cable is left? Please explain how you did it :3

He would have 9/12 yards left over because you have to create a common denominator which would be 12. so for 5/6 you would multiply by 2 so you have 10/12. 1/4 you have to multiply by 3 so you get 3/12. and 2/3 you have to multiply by 4 so you get 8/12. then you add them 10/12+3/12+8/12 = 21/12 which simplifies to 1 9/12 and because he used 1 yard he is left with 9/12.
final 9/12 yards

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