Subract the sum of 3a^4b-4b^3+c^2 & 6a^4b+3b^3-6c^2 from the sum of 6a^4b-4b^3-4c^2 & 2a^4b+4b^3+7c^

-a^4b + b^3 - 8c^2

Step-by-step explanation:

Sum of

3a^4b-4b^3+c^2 + 6a^4b+3b^3-6c^2

= 3a^4b + 6a^4b - 4b^3 + 3b^3 + c^2 - 6c^2

= 9a^4b - b^3 - 5c^2

Sum of

6a^4b-4b^3-4c^2 + 2a^4b+4b^3+7c^

= 6a^4b + 2a^4b - 4b^3 + 4b^3 - 4c^2 + 7c^2

= 8a^4b + 3c^2

Subtract

8a^4b + 3c^2 - (9a^4b - b^3 - 5c^2)

= 8a^4b + 3c^2 - 9a^4b + b^3 + 5c^2

= 8a^4b - 9a^4b + b^3 + 3c^2 + 5c^2

= -a^4b + b^3 - 8c^2

answer: answer: d) v= 1/6 bh  

step-by-step explanation:

since according to the given question,   a pyramid is placed inside a prism.

step-by-step explanation: