Solve each equation with the quadratic formula. (Show work please)

Let b=x

Such that b^2 =8b-8 will x^2=8x-8

Using the almighty quadratic formula

x1={-b+sqrt (b^2-4ac)}/2a

x2={-b-sqrt (b^2-4ac)}/2a

From the question

a=1

b=8

c=-8

x1={-8+sqrt (8^2-4(-8))}/2

x1=(-8+5.66)/2

x1=-1.17

x2={-8-sqrt (8^2-4(-8))}/2

x2=(-8-5.66)/2

x2=-6.83

:.(x1,x2)=(-1.17,-6.83)

Step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

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step-by-step explanation: