How many solutions does the system of equations have?(1 point) 3x=-12y+15 and x+4y=5
A-one
B-two
C-infinitely many
D-none

c

Step-by-step explanation:

First, I'll isolate the x in x+4y=5 to match with the other equation.

The new equation would be x= -4y+5

Next, we will multiply one equation by 3 and the other by -1 for both to match with the other.

-1(-12y + 15 = 3x )

3(-4y + 5 = x)

The new equations would be :

12y - 15 = -3x

-12y + 15 = 3x

Add the equations and you get

0 = 0

The equation has an infinite amount of solutions

b, i believe, but not sure.