If the distance from the center of a Ferris wheel to one of the seats is approximately 90 feet what is the distance traveled by a seated person, to the nearest foot, in four revolutions r=90 feet

2261.9 ft

Step-by-step explanation: One trip around is one circumference of a circle. The circumference is 2πr. That's 2(π)(90 ft) = 565.4867 ft. Multiply by 4 trips around for a total distance of 2261.9 ft If you care about significant figures, then you only have report  sig fig, so that's 2000 ft.

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.