Line q passes through the point (4,6)and (0,6). What is the equation for the line which is parpendicular to q and passes through the point (-2,3)

The equation of the line passing through the points (4, 6) and (0, 6) will be:

The graph of the equation y = 6 is also attached.

Step-by-step explanation:

The slope-intercept form of the line equation

where

Given the points

Finding the slope between (4, 6)and (0, 6).

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

               =  [6 - 6] / [0 - 4]

               = 0 / -4  

               = 0

Thus, the slope of the line = m = 0

The slope m = 0 means the line is horizontal.  Because the slope of the horizontal line is 0.

As the y-values are not changing with respect to the x-values.

Therefore,

The equation of the line passing through the points (4, 6) and (0, 6) will be:

The graph of the equation y = 6 is also attached.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

a

step-by-step explanation:

its wrong