What is the resistance of a 1.00X10^2 -Ω , a 2.50-kΩ , and a 4.00-k Ω resistor connected in parallel?

Therefore, the total Resistance:  R = 93.9 Ω

Step-by-step explanation:

Given

R₁ = 1 × 10²

R₂ = 2.5 kΩ = 2.5 × 10³ Ω

R₃ = 4  kΩ = 4 × 10³ Ω

Given that the given resisters are connected parallel, so using the formula to calculate the total Resistance R:

susbtituting R₁ = 1 × 10², R₂ = 2.5 × 10³ Ω, and R₃ = 4 × 10³ Ω

Multiply by LCM of R, 100, 2500, and 4000:   20000 R

simplify

Switch sides

Divide both sides by 213

Simplify

Ω

Therefore, the total Resistance:  R = 93.9 Ω

this is answer of 144 cubic meters

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