A logarithmic function of base ‘3’ has a vertical asymptote at the line x=1. Its graph contains the point (2,1). What is the equation of the function? 1) f(x)=log3 (x+1)
2) f(x)=log3(x-1)+1
3) f(x)=log3(x+1)+1
4) f(x)=log3(x)+1

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  2)  f(x) = log3(x -1) +1

Step-by-step explanation:

The vertical asymptote of the log function is normally x=0. In this function, it is moved to the right 1 unit. That is accomplished by replacing the function argument x with (x-1). Only one answer choice matches:

  f(x) = log3(x -1) +1

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a

what is the rest of the question? ?