The angle bisectors of AABC are AV, BV, and CV. They meet at a single point V. (In other words, V is the incenter of AABC.)
Suppose TV=18, CV=27, mZTCU=22°, and m2 SAV=32°.
Find the following measures.
Note that the figure is not drawn to scale.
B
mZSAU = 1
T
S
m 2 SBV =
V
SV = 0
А
U
Check

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

there would be 365 different 4 digit numbers

step-by-step explanation:

i belive that it is 365 because i asked google

homozygous. one is homozygous, while two is heterozygous.