Serena brought a total of 135 notebooks and pencils for her students. Each notebook cost 1.75 and each pencil cost 0.35. The total cost of her purchase was 122.85. How many pencils did Serena buy?

81 pencils

Step-by-step explanation:

1. Set up variables

Pencils = p

notebooks= n

2. Set up a system of equations

p+n= 135                             (The amount of supplies bought)

1.75n +0.35p = 122.85       (Equation for the cost)

3. Solve the system of equations (I'll use substitution)

    a)p= 135-n  (I just rearranged it)

    1.75n + 0.35p= 122.85

     b) Substitute the first equation into the second)

    1.75n + 0.35(135-n) = 122.85

     c) Solve!

    1.75n + 47.25 - 0.35n = 122.85

    1.4n = 75.6

     n= 54

Serena bought 54 notebooks!

4. Substitute the number of notebooks into the first equation

p +n = 135

p + 54= 135

p = 81

Serena bought 81 pencils!!!

I hope this helps

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0