−5(2x − 11) = 2(x − 32) − 25 x =

x = 119/13

1. Distribute -5(2x-11) = 2(x - 32) - 25x
-10x + 55 = 2x - 64 - 25x
2. Combine like terms
-10x + 55 = -23x - 64
3. Subtract 55 from both sides if the equation
-10x = -23x -119
4. Subtract the numbers -10x and -23x
5. Final x = 119/13

What are you asking ?

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.