Given \qquad m \angle ABD = 96^\circm∠ABD=96
∘
m, angle, A, B, D, equals, 96, degrees
\qquad m \angle CBD = 6x + 27^\circm∠CBD=6x+27
∘
m, angle, C, B, D, equals, 6, x, plus, 27, degrees
\qquad m \angle ABC = 7x - 9^\circm∠ABC=7x−9
∘
m, angle, A, B, C, equals, 7, x, minus, 9, degrees
Find m\angle CBDm∠CBDm, angle, C, B, D: