ON wednesday Eddy goes to a velodrome to train. He cycles the first lap of the track in 25 seconds. Each lap Eddy cycles takes him 1.6 seconds longer thatn the previous lap. Required:
a. Find the time in seconds, Eddy takes to cycle his tenth lap 2
b. Eddy cycles his last lap in 55.4 seconds. Find how many laps he has cycled on wednesday.
c. Find the total time in minutes, cycled by Eddy on Sunday.

Step-by-step explanation:

The data of timing for each lap will form a arthmetic progression ( AP ) with first term as 25 s  and common difference of 1.6 s .

a )

first term a = 25

common difference d = 1.6 .

10 th term of the series can be given by following formula

a₁₀ = 25 + ( 10-1 ) x 1.6

= 25 + 1.6 x 9

= 39.4 s

b )

Let n th be the last lap

a(n) = a + ( n-1 ) x d

55.4 = 25 + ( n- 1 ) x 1.6

n - 1 = 19

n = 20 .

c )

sum of all the term of AP

=(  first term + last term ) x no of term / 2

= (25 + 55.4 ) x 20 / 2

= 804 s .

= 804 / 60 min

= 13.4 min .

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following