Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K. How can a translation and a rotation be used to map ΔHJK to ΔLMN? Translate H to L and rotate about H until HK lies on the line containing LM. Translate K to M and rotate about K until HK lies on the line containing LM. Translate K to N and rotate about K until HK lies on the line containing LN. Translate H to N and rotate about H until HK lies on the line containing LN.

can someone answer this question plz

step-by-step explanation:

a

step-by-step explanation:

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p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).