What is the equation, in point-slope form, for a line that goes through (2, −6)(2, −6) and has a slope of −34−34 ?

y−6=34(x−2)y−6=34(x−2)

y−6=−34(x+2)y−6=−34(x+2)

y+6=−34(x+2)y+6=−34(x+2)

y+6=−34(x−2)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180