An empty sand pit eeighs 6kg. The wight increases to 50kg when filled with sand. A different sand pit is 14% heavier but holds 22% less sand. Calculate the weight of this sand pit when it is full of sand

The weight of this sand pit when it is full of sand is 41.16kg

Step-by-step explanation:

For the first sand pit

It weighs 6kg and weight increases to 50kg when filled with sand.

Therefore, it can hold 50kg - 6kg = 44kg of sand

For the second sand pit

From the question, it is 14% heavier, that is, the weight will be

6kg + (14/100) × 6kg  = 6kg + 0.84kg

= 6.84kg

∴ The weight of the different sand pit is 6.84kg

Also from the question, it holds 22% less sand, that is, the weight of the sand it holds will be

44kg - (22/100) × 44kg = 44kg - 9.68kg

= 34.32kg

∴The weight of sand it holds is 34.32kg

The weight of this sand pit when it is full of sand is the sum of the weight of the sand pit and the weight pf sand it holds, that is,

Weight of sand pit = 6.84kg + 34.32kg = 41.16kg

Hence, the weight of this sand pit when it is full of sand is 41.16kg

no problobm

step-by-step explanation:

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i graphed to on desmos.